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68 lines
1.5 KiB
Bash
Executable File
68 lines
1.5 KiB
Bash
Executable File
#!/bin/sh
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# see if chgrp can change the group of a symlink
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if test "$VERBOSE" = yes; then
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set -x
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chgrp --version
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fi
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. $srcdir/../group-names
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pwd=`pwd`
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tmp=slink.$$
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trap 'status=$?; cd $pwd; rm -rf $tmp && exit $status' 0
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trap '(exit $?); exit' 1 2 13 15
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framework_failure=0
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mkdir $tmp || framework_failure=1
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cd $tmp || framework_failure=1
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if test $framework_failure = 1; then
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echo 'failure in testing framework' 1>&2
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(exit 1); exit
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fi
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set _ $groups; shift
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g1=$1
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g2=$2
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touch f
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ln -s f symlink
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chgrp $g2 symlink 2> /dev/null
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set _ `ls -l symlink`
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g=$5
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test "$g" = $g2 || {
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cat <<EOF 1>&2
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$0: skipping this test; your system doesn't support changing
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the owner or group of a symbolic link.
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EOF
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(exit 77); exit
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}
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fail=0
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chgrp $g1 f
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set _ `ls -l f`; g=$5; test "$g" = $g1 || fail=1
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chgrp $g2 symlink || fail=1
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set _ `ls -l f`; g=$5; test "$g" = $g1 || fail=1
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set _ `ls -l symlink`; g=$5; test "$g" = $g2 || fail=1
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# This should not change the group of f.
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chgrp $g2 symlink || fail=1
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set _ `ls -l f`; g=$5; test "$g" = $g1 || fail=1
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set _ `ls -l symlink`; g=$5; test "$g" = $g2 || fail=1
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chgrp $g2 f
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set _ `ls -l f`; g=$5; test "$g" = $g2 || fail=1
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# This *should* change the group of f.
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# Though note that the diagnostic you'd get with -c is misleading in that
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# it says the `group of `symlink'' has been changed.
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chgrp --dereference $g1 symlink
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set _ `ls -l f`; g=$5; test "$g" = $g1 || fail=1
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set _ `ls -l symlink`; g=$5; test "$g" = $g2 || fail=1
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(exit $fail); exit
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