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f32d5071b7
If the provided Hash doesn't have a default proc, we know for sure that we'll never call into user provided code, hence the string we allocate to access the Hash can't possibly escape. So we don't actually have to allocate it, we can use a fake_str, AKA a stack allocated string. ``` compare-ruby: ruby 3.5.0dev (2025-02-10T13:47:44Z master 3fb455adab) +PRISM [arm64-darwin23] built-ruby: ruby 3.5.0dev (2025-02-10T17:09:52Z opt-gsub-alloc ea5c28958f) +PRISM [arm64-darwin23] warming up.... | |compare-ruby|built-ruby| |:----------------|-----------:|---------:| |escape | 3.374k| 3.722k| | | -| 1.10x| |escape_bin | 5.469k| 6.587k| | | -| 1.20x| |escape_utf8 | 3.465k| 3.734k| | | -| 1.08x| |escape_utf8_bin | 5.752k| 7.283k| | | -| 1.27x| ```
44 lines
1.0 KiB
YAML
44 lines
1.0 KiB
YAML
prelude: |
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# frozen_string_literal: true
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STR = ((("a" * 31) + "<") * 1000).freeze
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STR_UNICODE = ((("a" * 30) + "\u2028") * 1000).freeze
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ESCAPED_CHARS_BINARY = {
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"\u2028".b => '\u2028'.b,
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"\u2029".b => '\u2029'.b,
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">".b => '\u003e'.b.freeze,
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"<".b => '\u003c'.b.freeze,
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"&".b => '\u0026'.b.freeze,
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}
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BINARY_PATTERN = Regexp.union(ESCAPED_CHARS_BINARY.keys)
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ESCAPED_CHARS = {
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"\u2028" => '\u2028',
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"\u2029" => '\u2029',
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">" => '\u003e',
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"<" => '\u003c',
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"&" => '\u0026',
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}
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ESCAPE_PATTERN = Regexp.union(ESCAPED_CHARS.keys)
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benchmark:
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escape: |
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str = STR.dup
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str.gsub!(ESCAPE_PATTERN, ESCAPED_CHARS)
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str
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escape_bin: |
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str = STR.b
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str.gsub!(BINARY_PATTERN, ESCAPED_CHARS_BINARY)
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str.force_encoding(Encoding::UTF_8)
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escape_utf8: |
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str = STR_UNICODE.dup
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str.gsub!(ESCAPE_PATTERN, ESCAPED_CHARS)
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str
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escape_utf8_bin: |
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str = STR_UNICODE.b
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str.gsub!(BINARY_PATTERN, ESCAPED_CHARS_BINARY)
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str.force_encoding(Encoding::UTF_8)
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